(2x^2-3x-)(x^2+2x+)/2x-3=0

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Solution for (2x^2-3x-)(x^2+2x+)/2x-3=0 equation: 



(2x^2-3x-)(x^2+2x+)/2x-3=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We multiply all the terms by the denominator


(2x^2-3x-)(x^2+2x+)-3*2x=0

Wy multiply elements

(2x^2-3x-)(x^2+2x+)-6x=0

We add all the numbers together, and all the variables

-6x+(2x^2-3x-)(x^2+2x+)=0

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